-y^2+2y-12=0

Solution for -y^2+2y-12=0 equation:

Simplifying
-1y2 + 2y + -12 = 0

Reorder the terms:
-12 + 2y + -1y2 = 0

Solving
-12 + 2y + -1y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
-1 the coefficient of the squared term: 

Divide each side by '-1'.
12 + -2y + y2 = 0

Move the constant term to the right:

Add '-12' to each side of the equation.
12 + -2y + -12 + y2 = 0 + -12

Reorder the terms:
12 + -12 + -2y + y2 = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -2y + y2 = 0 + -12
-2y + y2 = 0 + -12

Combine like terms: 0 + -12 = -12
-2y + y2 = -12

The y term is -2y.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2y + 1 + y2 = -12 + 1

Reorder the terms:
1 + -2y + y2 = -12 + 1

Combine like terms: -12 + 1 = -11
1 + -2y + y2 = -11

Factor a perfect square on the left side:
(y + -1)(y + -1) = -11

Can't calculate square root of the right side.

The solution to this equation could not be determined.